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Showing posts with the label UnboundLocalError

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How to Build CI/CD Pipeline: GitHub to AWS

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 Creating a CI/CD pipeline to deploy a project from GitHub to AWS can be done using various AWS services like AWS CodePipeline, AWS CodeBuild, and optionally AWS CodeDeploy or Amazon ECS for application deployment. Below is a high-level guide on how to set up a basic GitHub to AWS pipeline: Prerequisites AWS Account : Ensure access to the AWS account with the necessary permissions. GitHub Repository : Have your application code hosted on GitHub. IAM Roles : Create necessary IAM roles with permissions to interact with AWS services (e.g., CodePipeline, CodeBuild, S3, ECS, etc.). AWS CLI : Install and configure the AWS CLI for easier management of services. Step 1: Create an S3 Bucket for Artifacts AWS CodePipeline requires an S3 bucket to store artifacts (builds, deployments, etc.). Go to the S3 service in the AWS Management Console. Create a new bucket, ensuring it has a unique name. Note the bucket name for later use. Step 2: Set Up AWS CodeBuild CodeBuild will handle the build proces
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The Quick and Easy Way to Fix Python UnboundLocalError

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Here is the easy way to fix the issue of the Python UnboundLocalError, allowing users to resolve any problems quickly. Python UnboundLocalError While the variable in the function has already been defined, during execution, the result prints with an error of UnboundLocalError. Below, you will find an example that explains the issue and resolution. Error: file 'example.txt' not found Traceback (most recent call last): File "main.py", line 16, in <module> open_file("example.txt") File "main.py", line 11, in open_file if f: UnboundLocalError: local variable 'f' referenced before assignment ** Process exited - Return Code: 1 ** Press Enter to exit terminal Python program using try, except and finally Below program explains how to use try, except and finally blocks in python. But during the execution, it prints UnboundLocalError. Program using try, except and finally # Define a function that may raise an exception def open_file(filename):  
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