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How to Build CI/CD Pipeline: GitHub to AWS

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 Creating a CI/CD pipeline to deploy a project from GitHub to AWS can be done using various AWS services like AWS CodePipeline, AWS CodeBuild, and optionally AWS CodeDeploy or Amazon ECS for application deployment. Below is a high-level guide on how to set up a basic GitHub to AWS pipeline: Prerequisites AWS Account : Ensure access to the AWS account with the necessary permissions. GitHub Repository : Have your application code hosted on GitHub. IAM Roles : Create necessary IAM roles with permissions to interact with AWS services (e.g., CodePipeline, CodeBuild, S3, ECS, etc.). AWS CLI : Install and configure the AWS CLI for easier management of services. Step 1: Create an S3 Bucket for Artifacts AWS CodePipeline requires an S3 bucket to store artifacts (builds, deployments, etc.). Go to the S3 service in the AWS Management Console. Create a new bucket, ensuring it has a unique name. Note the bucket name for later use. Step 2: Set Up AWS CodeBuild CodeBuild will handle the build proces

The Quick and Easy Way to Fix Python UnboundLocalError

Here is the easy way to fix the issue of the Python UnboundLocalError, allowing users to resolve any problems quickly.


UnboundLocalError



Python UnboundLocalError

While the variable in the function has already been defined, during execution, the result prints with an error of UnboundLocalError. Below, you will find an example that explains the issue and resolution.

Error: file 'example.txt' not found
Traceback (most recent call last):
File "main.py", line 16, in <module>
open_file("example.txt")
File "main.py", line 11, in open_file
if f:
UnboundLocalError: local variable 'f' referenced before assignment


** Process exited - Return Code: 1 **

Press Enter to exit terminal


Python program using try, except and finally

Below program explains how to use try, except and finally blocks in python. But during the execution, it prints UnboundLocalError.


Program using try, except and finally

# Define a function that may raise an exception
def open_file(filename):
    try:
        f = open(filename, "r")
        contents = f.read()
    except FileNotFoundError:
        print(f"Error: file '{filename}' not found")
    else:
        print(f"Contents of file '{filename}':\n{contents}")
    finally:
        if f:
            f.close()
            print(f"File '{filename}' has been closed.")

# Call the function with a valid filename
open_file("example.txt")

# Call the function with an invalid filename
open_file("invalid.txt")


The output:

Error: file 'example.txt' not found
Traceback (most recent call last):
  File "main.py", line 16, in <module>
    open_file("example.txt")
  File "main.py", line 11, in open_file
    if f:
UnboundLocalError: local variable 'f' referenced before assignment


** Process exited - Return Code: 1 **
Press Enter to exit terminal

Resolution for UnboundLocalError

In the function, before the try block, add f = None. That resolves the issue. Here is the corrected program.

Corrected program

# Define a function that may raise an exception
def open_file(filename):
    try:
        f = None
        f = open(filename, "r")
            contents = f.read()
    except FileNotFoundError:
        print(f"Error: file '{filename}' not found")
    else:
        print(f"Contents of file '{filename}':\n{contents}")
    finally:
        if f:
            f.close()
            print(f"File '{filename}' has been closed.")

# Call the function with a valid filename
open_file("example.txt")

# Call the function with an invalid filename
open_file("invalid.txt")


The output is:

Error: file 'example.txt' not found
Error: file 'invalid.txt' not found


** Process exited - Return Code: 0 **
Press Enter to exit terminal


Summary

  • Return statement not coded in the function. As a result, it gave UnboundLocalError.
  • A function returns the None object by default if the control flow falls off the end of the function body without running into a return statement.

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