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 Regular expressions (regex) are powerful tools for pattern matching and text manipulation in Python. Here are five Python regex examples with explanations: 01 Matching a Simple Pattern import re text = "Hello, World!" pattern = r"Hello" result = re.search(pattern, text) if result:     print("Pattern found:", result.group()) Output: Output: Pattern found: Hello This example searches for the pattern "Hello" in the text and prints it when found. 02 Matching Multiple Patterns import re text = "The quick brown fox jumps over the lazy dog." patterns = [r"fox", r"dog"] for pattern in patterns:     if re.search(pattern, text):         print(f"Pattern '{pattern}' found.") Output: Pattern 'fox' found. Pattern 'dog' found. It searches for both "fox" and "dog" patterns in the text and prints when they are found. 03 Matching Any Digit   import re text = "The price of the

How to Count Vowels in Input Quickly

Here you'll know how python counts characters in the input. This is an interview question asked recently.

How to Count Vowels in Input Quickly

How to Count Vowels in Input String

Below is the Interview Question

Vowels = ('aeiou')

You need to check any vowels are present in the input string. Vowels means 'a', 'e', 'i', 'o', 'u'. The below function checks each character of input and compares it with the Vowels.

3 Steps to Count Vowels in Input

You can achieve this in three steps.

1. Create a function called 'my_vowel' (the name up to you)
2. Use Set & Intersection Method
3. Run the function

1. Created 'my_vowel' Function

#This function finds vowel counts
#welcome to my function
""" Optional description """
def my_vowel(a):
    a_1= vowels.intersection(set(a))
# initialized the dictionary
    found = {'a' : 0, 'e' : 0, 'i' : 0, 'o' :, 'u' : 0}
    for indx in a_1:
        if indx in vowels:
            found[indx] += 1
     for k, v sorted(found.items():

I used vim editor to create a .py module with the name vowel.py. Below is the actual code.

Logic to count vowels in input

2. Used Set & Intersection Methods

- Set method converts the input string as a set (you aware about this in mathes)

- Intersect method extracts each character and compares it with a Dictionary (that I'have already defined).

- I used the IF condition to work this logic correctly and validate each character.

3. Result

I have imported the .py module to Python3. Then, I have supplied an input string. It is then validated and given the counts.

The result says, in the given string the vowels are like this:
a -> 0
e -> 1
i -> 0
o -> 1
u -> 0

using function counting of vowels


  • As expected in the result we got counts for matching vowels.
  • It's very tricky and asked in most of the interviews
  • Test your function with various strings and improve your knowledge.


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