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Mastering flat_map in Python with List Comprehension

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Introduction In Python, when working with nested lists or iterables, one common challenge is flattening them into a single list while applying transformations. Many programming languages provide a built-in flatMap function, but Python does not have an explicit flat_map method. However, Python’s powerful list comprehensions offer an elegant way to achieve the same functionality. This article examines implementation behavior using Python’s list comprehensions and other methods. What is flat_map ? Functional programming  flatMap is a combination of map and flatten . It transforms the collection's element and flattens the resulting nested structure into a single sequence. For example, given a list of lists, flat_map applies a function to each sublist and returns a single flattened list. Example in a Functional Programming Language: List(List(1, 2), List(3, 4)).flatMap(x => x.map(_ * 2)) // Output: List(2, 4, 6, 8) Implementing flat_map in Python Using List Comprehension Python’...

How to Count Vowels in Input Quickly

Here you'll know how python counts characters in the input. This is an interview question asked recently.

How to Count Vowels in Input Quickly


How to Count Vowels in Input String


Below is the Interview Question

Vowels = ('aeiou')

You need to check any vowels are present in the input string. Vowels means 'a', 'e', 'i', 'o', 'u'. The below function checks each character of input and compares it with the Vowels.

3 Steps to Count Vowels in Input


You can achieve this in three steps.

1. Create a function called 'my_vowel' (the name up to you)
2. Use Set & Intersection Method
3. Run the function

1. Created 'my_vowel' Function


#!usr/bin/python
#This function finds vowel counts
#welcome to my function
""" Optional description """
def my_vowel(a):
    vowels=set('aeiou')
    a_1= vowels.intersection(set(a))
# initialized the dictionary
    found = {'a' : 0, 'e' : 0, 'i' : 0, 'o' :, 'u' : 0}
    for indx in a_1:
        if indx in vowels:
            found[indx] += 1
     for k, v sorted(found.items():
        print(k,v)






I used vim editor to create a .py module with the name vowel.py. Below is the actual code.


Logic to count vowels in input


2. Used Set & Intersection Methods

- Set method converts the input string as a set (you aware about this in mathes)

- Intersect method extracts each character and compares it with a Dictionary (that I'have already defined).

- I used the IF condition to work this logic correctly and validate each character.


3. Result

I have imported the .py module to Python3. Then, I have supplied an input string. It is then validated and given the counts.

The result says, in the given string the vowels are like this:
a -> 0
e -> 1
i -> 0
o -> 1
u -> 0

using function counting of vowels


Bottom-line

  • As expected in the result we got counts for matching vowels.
  • It's very tricky and asked in most of the interviews
  • Test your function with various strings and improve your knowledge.

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