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SQL Interview Success: Unlocking the Top 5 Frequently Asked Queries

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 Here are the five top commonly asked SQL queries in the interviews. These you can expect in Data Analyst, or, Data Engineer interviews. Top SQL Queries for Interviews 01. Joins The commonly asked question pertains to providing two tables, determining the number of rows that will return on various join types, and the resultant. Table1 -------- id ---- 1 1 2 3 Table2 -------- id ---- 1 3 1 NULL Output ------- Inner join --------------- 5 rows will return The result will be: =============== 1  1 1   1 1   1 1    1 3    3 02. Substring and Concat Here, we need to write an SQL query to make the upper case of the first letter and the small case of the remaining letter. Table1 ------ ename ===== raJu venKat kRIshna Solution: ========== SELECT CONCAT(UPPER(SUBSTRING(name, 1, 1)), LOWER(SUBSTRING(name, 2))) AS capitalized_name FROM Table1; 03. Case statement SQL Query ========= SELECT Code1, Code2,      CASE         WHEN Code1 = 'A' AND Code2 = 'AA' THEN "A" | "A
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Best Practices for Handling Duplicate Elements in Python Lists

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Here are three awesome ways that you can use to remove duplicates in a list. These are helpful in resolving your data analytics solutions.


Methods to remove list duplicates


 01. Using a Set

Convert the list into a set, which automatically removes duplicates due to its unique element nature, and then convert the set back to a list.


Solution:

original_list = [2, 4, 6, 2, 8, 6, 10]

unique_list = list(set(original_list))


02. Using a Loop

Iterate through the original list and append elements to a new list only if they haven't been added before.

Solution:

original_list = [2, 4, 6, 2, 8, 6, 10]

unique_list = []

for item in original_list:

    if item not in unique_list:

        unique_list.append(item)


03. Using List Comprehension

Create a new list using a list comprehension that includes only the elements not already present in the new list.


Solution:

original_list = [2, 4, 6, 2, 8, 6, 10]

unique_list = []

[unique_list.append(item) for item in original_list if item not in unique_list]

All three methods will result in unique_list containing only the distinct elements from the original_list. Keep in mind that the order of elements might not be preserved using the set approach as sets are unordered collections. The loop and list comprehension methods will maintain the order of the elements.


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